The school call is so far away from me, but I have not yet lost the skill of solving dodgy mathematical examples.

Mathematics classes They help not only to master one of the fundamental sciences, but also bring many other benefits. A person learns to work with numbers in everyday life, uses the knowledge gained in professional activities, and more easily perceives technological innovations. In addition, mathematics classes develop logical and abstract thinking, teach a creative approach.



Today's edition. "Site" It invites readers to consider a few similar examples. However, in each case there will be a small detail that will make the decision different. This will show how attentive students have to be, who always have to give the right answers.

Mathematics classes
  1. In the first example, we have double brackets at the very end of the example. It is necessary to remember how to act in such a case (and what the mathematical rules say about all this). Solve this example without tips and a calculator. Don’t forget to write down or remember your answer in this case.



  2. The second example is the only one that differs in that there are no brackets. So it's the easiest thing to do. Although the numbers are the same, the answer will be different. Therefore, try to decide carefully and without haste.



  3. In the third example, there are brackets at the beginning and at the end. For many adults who have long forgotten mathematical wisdom, this can be a daunting task. We believe that you will be able to give the right answer here.



  4. In the last task there are only one brackets, but they show off in the middle of the example. Will there be a unique answer that has not been found in any of the previous examples? Remember the number and check our decisions in the second part of the article.





Tips and solutions
  1. The rules of mathematics say that actions are first performed in brackets that are inside. So first we add, then multiply, and then divide. Then it will look like this: 8 ÷ (2 × (1 + 3)) = 8 ÷ (2 × 4) = 8 ÷ 8 = 1.



  2. Since there are no brackets in the second example, we solve everything from left to right: division, multiplication and addition. The solution is 8 ÷ 2 × 1 + 3 = 4 × 1 + 3 = 4 + 3 = 7.



  3. The third example is the easiest to solve. After all, here simply perform alternate actions in brackets and multiply what happened. It looks like (8 ÷ 2) × (1 + 3) = 4 × 4 = 16.



  4. The fourth example will be similar to the second. And although in the decision itself the sequence of actions will be different, but the result will be the same. Namely: 8 ÷ (2 × 1) + 3 = 8 ÷ 2 + 3 = 4 + 3 = 7.





Did it work out? Share your answers in the comments. Also solve our other examples. And also try to deal with tricky puzzles that can spin the head of any adult. Although the students are quite dexterous here.

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