The task, which will require all logic and observation, find an extra person in the picture.

Problems of ingenuity always interest the audience. This can be done alone or with another person (to figure out who is smarter). And you can try to solve everything together with children, which will instantly turn the decision process into a fun and noisy fun, where all sorts of options are invented and tested one by one.



So today's editorial office. "Site" I found a few more puzzles that will be useful and exciting to solve in any company. Some answers will be quite easy, but when looking for others you will have to think. Will it work out?

Find an extra hero.

1. You've seen your first assignment before. Four men stand next to a newly built doghouse. A happy dog looks up at them gratefully. This white-eared guard knows exactly who worked on the construction of the booth, and who just passed by. Find an extra hero.. 536175
   
   
   
   
2. The second task is already more difficult, because here you have to deal with numbers. We have unusual examples where the usual figures are hidden behind images of snowflakes, trees and snowmen. Can you figure out what to do to solve the bottom example?
   
   
   
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3. Finally, we found a rather complex problem in which you need to find out which integers are hiding behind vegetables. And we have only the total number on the scales - 28. There is room for different options, but what is the right answer? Find a non-obvious solution here. Check out our tips and answers below.
   
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Tips and answers

1. It seems that the man on the far left painted this box, because the color of the roof clearly coincides with the color of his paint. The citizen with the saw probably dusted the boards from which the booth was knocked down. A man with a hammer was making a box. As for the young man with a brick, he is the fourth extra. In his hand is a brick that has nothing to do with the box.
   
   
   
   
2. If the sum of two snowflakes is equal to 18, then one snowflake should hide 18 ÷ 2 = 9. From the second example we find that the snowman is 27 ÷ 9 = 3. Then behind the tree hides 24 ÷ 3 = 8. Then we can easily find the sum to solve the lower example: 9 + 8 + 3 = 20.

If the total weight of 28 units and the scales are in equilibrium, the weight of the left and right sides is the same and equals 28 ÷ 2 = 14 units. By the same principle, we understand that on the lower scales, each of the available sides weighs 14 ÷ 2 = 7 units. For a better understanding, we will point this out in the picture below.

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Paying attention to the right side, we notice that two tomatoes and eggplant are equal in weight to carrot and eggplant. Two tomatoes are equal in weight to one carrot. Now let's look at the left side. If the tomato, carrot and onion weigh only 7 units, the tomato can weigh either 1, or 2. After all, if a tomato weighs three or more, then together with a carrot that is twice as heavy, the total weight will be too large.

If the tomato weighs 1, then the carrot weighs 2, and the onion weighs 7 – 1 – 2 = 4. But the far left ligament shows us that 1 onion weighs less than three tomatoes, so a tomato cannot weigh 1. The tomato weighs 2. Then the carrot is 2 × 2 = 4. And the weight of the onions will be 7 – 2 – 4 = 1. When we check the left side, we see that everything fits together. Then from the right side we find the weight of eggplant: 7 - 2 - 2 = 3.





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Tell us in the comments how you searched and found the answers. We hope that solving these problems brightened up a few minutes for you. Also solve other puzzles. Or try to deal with tricky mathematical examples from the school curriculum.